Daryl,where does it say in the book the left arm flying wedge IS THE PLANE LINE?.Now you've got me confused!.I always took it that the HANDS AND THE CLUBHEAD DEFINE THE PLANE.Iknow it says in6-B-3-O-1"the entire left arm ,the clubshaft and the back of the left hand are always positioned against the same flat plane-[i]the plane of the left wristcock motion.IALWAYS THOUGHT THIS WAS NOT THE INCLINED PLANE THAT THE HANDS TRAVEL ON -BECAUSE OF THE SHOULDER ROTATION.
Daryl,where does it say in the book the left arm flying wedge IS THE PLANE LINE?.Now you've got me confused!.I always took it that the HANDS AND THE CLUBHEAD DEFINE THE PLANE.Iknow it says in6-B-3-O-1"the entire left arm ,the clubshaft and the back of the left hand are always positioned against the same flat plane-[i]the plane of the left wristcock motion.IALWAYS THOUGHT THIS WAS NOT THE INCLINED PLANE THAT THE HANDS TRAVEL ON -BECAUSE OF THE SHOULDER ROTATION.
I was confused, but not anymore. Sorry for making it confusing.
Question:
If the wrist cock motion keeps the clubshaft and left arm on the same flat plane, and, the left arm is not on the inclined plane, then how does the clubshaft stay on the inclined plane when cocking?
Answer: It doesn't.
PS. if I said that the Left Arm Flying Wedge was the Plane Line then it was a misprint.
I was confused, but not anymore. Sorry for making it confusing.
Question:
If the wrist cock motion keeps the clubshaft and left arm on the same flat plane, and, the left arm is not on the inclined plane, then how does the clubshaft stay on the inclined plane when cocking?
Answer: It doesn't.
PS. if I said that the Left Arm Flying Wedge was the Plane Line then it was a misprint.
Daryl,the hands and clubface define the plane.The left entire left arm, clubshaft and the back of the left hand are always positioned against the same flat plane -NOT IMO "THE "PLANE ,but "their" own flat plane.Because of the space between the left shoulder and the centre of the pivot ,rotation moves the left shoulder off plane-but Homer never referred to the plane (well only briefly)in terms of the left shoulder.I think I understand what you are getting at -the hands and clubshaft cannot be on plane if the left arm flying wedge is not on plane.Hmmmmm-Ithink they can ......GO FOR IT MATE
Daryl,the hands and clubface define the plane.The left entire left arm, clubshaft and the back of the left hand are always positioned against the same flat plane -NOT IMO "THE "PLANE ,but "their" own flat plane.Because of the space between the left shoulder and the centre of the pivot ,rotation moves the left shoulder off plane-but Homer never referred to the plane (well only briefly)in terms of the left shoulder.I think I understand what you are getting at -the hands and clubshaft cannot be on plane if the left arm flying wedge is not on plane.Hmmmmm-Ithink they can ......GO FOR IT MATE
G'day Mate.
Here it goes. I think I found the answers. Get your dowels out.
Query:
If the wrist cock motion keeps the Clubshaft and left arm on the same flat plane, the plane of the Left Arm Flying Wedge, and, if the left arm is not on the inclined plane, then how does the Clubshaft stay on the inclined plane when cocking?
Statements:
I know, only by reading HK, that the left arm and Clubshaft must be on the same plane; the Plane of the Left Wrist Cock. Otherwise you destroy the Left Arm Flying Wedge.
6 -B-3-O-1. "…the entire Left Arm, the Clubshaft and the back of the Left Hand are ALWAYS positioned against the same flat plane - the plane of the Left Wristcock motion.”
The above statement seems to conflict with the following statement:
HK said that: 2-F. “Whenever the Clubshaft is parallel to the ground it must also be parallel to the baseline of the Inclined Plane..” “Otherwise, the end of the club that is closest to the ground must be pointing at the base line of the inclined plane – or extension of that line, even if they must be extended to the horizon.”
If you put a club in your left hand and keep the Clubshaft on plane with your left arm, you can’t have it parallel to the baseline of the inclined plane when it is horizontal to the ground nor can you point either end of the Clubshaft at the base line of the inclined plane and have the Clubshaft lying flat against the inclined plane unless you bend your left wrist. Bent Visually or Geometrically.
I always thought that the Clubshaft and hands had to lie flat against the Inclined Plane. Every time we see an inclined plane board such as all of those in the little yellow book and those we’ve constructed ourselves and the Circle Tube Planes that you can purchase from any practice aid web-site has reinforced this generally agreed FACT, that being On Plane Means That The Clubshaft Lies Flat Against, On, or In, the Inclined Plane.
And, to make things worse, 2-N-0. “AS LONG AS THE CLUBSHAFT HOLDS A STRAIGHT LINE ELATIONSHIP TO A STRAIGHT LINE – POINTING AT A STRAIGHT LINE.” Which reaffirms 2-F.
Solution:
In his thread “Left Arm Flying Wedge and Plane” by Tongzilla on 1-14-2006
Tong asked if the left arm flying wedge was parallel to the plane. In post # 26, annikan skywalker almost had the answer but the thread was never finished. No conclusions were agreed on. No solution. But he hinted that Only with a Rotated Shoulder Turn, on a Square Shoulder Plane and when the waist bend is at enough angle so that the shoulders will be on plane while turning, will you have the Left Arm Flying Wedge and Wristcock lie on the same flat Inclined Plane.
What defines the Plane? It passes through the Ball and whatever one of the five reference points you decide to use. Elbow, Turned Shoulder, Squared Shoulder, Turning Shoulder or Hands Only.
What goes up, back and in on plane and down, forward and out on plane?
Hands and their pressure points. Not the Clubshaft if you want to keep your left arm flying wedge.
Your hands and pressure points travel along the inclined plane as PP#3 traces its straight base line helping the Left Arm Flying Wedge to keep the Clubshaft pointing at it. (See correction below)
The clubshaft does not need to lie flat on the incline plane (turned shoulder) to be pointing at the baseline of the inclined Turned Shoulder Plane. It has its own relationship with the baseline of the inclined plane (the Left Arm Flying Wedge).
I didn’t know that.
Correction: With flatter (flatter than square shoulder) plane angles the clubshaft will point to a line parallel but outside the base line of the inclined plane.
Added 5/24/2006
More information: The club stays on its own angle during the backstroke and downstroke and the #3 pressure point travels up and down the incline plane raising and lowering the clubshaft.
This is different than what Ben Doyle said in his video, "How to build a G.O.L.F. swing", that the clubshaft changes its angle (gets steeper) during the backswing.
So, the Left Arm Flying Wedge has its own plane (with the Clubshaft). The baseline of this plane moves away (out) from the base line of the inclined plane from Impact Fix to the top (or end) of the backstroke, then moves in toward the base line of the inclined plane during the downstroke.
I believe that the hands and clubshaft can be on the turned shoulder plane even though the left arm is not.So I suppose I am saying that the plane of the left arm flying wedge is not the same as the inclined plane but the hands and clubshaft are on both-they intersect at the hands-the #3PP.
I believe that the hands and clubshaft can be on the turned shoulder plane even though the left arm is not.So I suppose I am saying that the plane of the left arm flying wedge is not the same as the inclined plane but the hands and clubshaft are on both-they intersect at the hands-the #3PP.
I agree that both planes intersect at the #3 pressure point. But the Left arm flying wedge requires a flat left wrist so that the clubshaft, wristcock, and left arm lie in the same flat plane.
You agree they intersect which implies two planes.
I agree that both planes intersect at the #3 pressure point. But the Left arm flying wedge requires a flat left wrist so that the clubshaft, wristcock, and left arm lie in the same flat plane.
You agree they intersect which implies two planes.
No -If I thought there were two planes I would say so .I think they intersect but the hands/clubshaft are subject to the rotation of the shoulders which takes the left arm "off plane"-but it has it's "own plane"which is not the inclined plane of the right forearm.An argument could be made that you would have to bend the left wrist to keep the back of the left hand parallel to the plane-and Homer did not dismiss this so long as you get it flat at impact.If the left wrist stays flat throughout the swing then I would say that it is the #3pp that can stay on the intersection of the "two planes"but that is still the selected plane -back- in -up- down -out- forward.Or for example the turned shoulder plane o.k. where are THE BIG GUNS!
Hybrid Mode
