[Mike O]

So, I presume you all look at Pivot as a BEARING rather then it is a Electric Motor

Now, another related question. I always believe that Hitting the ball further is all about be able to generate more speed.

Now, Pivot is a massive vehicle which transports the Power Package Assembly, therefore if I am correct Pivot is not giving any speed but only the hands are (Endless Belt effect)
So could I have a firm sort of defination about Pivot Power, according to the previous debate, pivot is just a Bearing and have minimum Kinetic Energy. But if we look at it from a different Angle the inside moving the outside. So is the pivot a Electric Motor or It is a Bearing?

Please really give some precise thought to it, rather then just answer the question from the book.

Oz,
I've highlighted the part of your post that I am addressing-
Now, another related question. I always believe that Hitting the ball further is all about be able to generate more speed.

I'm not very good with equations and physics - so I might be a duck in hunting season on this one but it's not just speed that's required to hit the ball further. It's the formula for Kinetic Energy that's important- KE=1/2mass x Velocity squared

So the greater the pivot lag the greater the mass is rotating around creating the following two examples where the faster velocity of the clubhead in example two produces a much lower kinetic energy amount - due to the lower mass.
Example 1: 1/2 x 180= 90 x (50 x 50) = 225,000
Example 2: 1/2 x 90 = 45 x (60 x 60) = 162,000

So in the first example you've got less velocity 50 but more mass 180 and a total kinetic energy applied to the ball of 225,000

Second example you've got less mass 90 but an increased velocity of the clubhead of 60 squared, creating a total of kinetic energy applied to the ball of 162,000.

So for a practical example, if you throw the club away on the downswing- it starts to swing around a much shorter radius (left wrist vs the left shoulder) and because of that the speed in mph increases significantly but since you've got little mass in the clubhead itself and you've added nothing to it- the kinetic energy is very low.

I'm sure someone can verify or refute the principle involved here- and maybe even be able to restate the equation with the appropriate unit labels, etc.

Oz- I know this just addresses one issue in your post- you may still have others.