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Old 02-20-2007, 03:29 PM
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Mathew Mathew is offline
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Join Date: Jan 2005
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Originally Posted by armourall View Post
What would you think if I stated it like this...

Original Selection:
  1. The player originally picked goat 1.
  2. The player originally picked goat 2.
  3. The player originally picked the car.
Chances of originally selecting the car: 1 in 3.
Correct...

Quote:
Second Selection:[list=1][*]The player originally picked goat 1. The door with goat 2 is revealed. The remaining door has the car.
Correct

Quote:
[*]The player originally picked goat 2. The door with goat 1 is revealed. The remaining door has the car.
Correct

Quote:
  • The player originally picked the car. The door with goat 1 is revealed. The remaining door has goat 2.
  • The player originally picked the car. The door with goat 2 is revealed. The remaining door has goat 1.
Chances of switching and selecting the car: 2 in 4 (1 in 2)
Nope - there is only 1 car behind the doors not two....

Just because there are four permutations of what can occur doesn't mean you have four choices. It really doesn't matter if you eliminate goat 1 or goat 2 when you have picked the car. If you switch, you will lose either way....



Make this any easier to understand ?
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